-- File Name: Sean_Blackburne_tsqlchallenge_15.sql
select
RowVal as Row,
case [1] when 1 then 'X' else '' end as [1],
case [2] when 1 then 'X' else '' end as [2],
case [3] when 1 then 'X' else '' end as [3],
case [4] when 1 then 'X' else '' end as [4],
case [5] when 1 then 'X' else '' end as [5],
case [6] when 1 then 'X' else '' end as [6],
case [7] when 1 then 'X' else '' end as [7],
case [8] when 1 then 'X' else '' end as [8],
case [9] when 1 then 'X' else '' end as [9]
from
(
select
RowVal,
[1],
[2],
[3],
[4],
[5],
[6],
[7],
[8],
[9]
from
(
select
Row,Row as RowVal,Col
from @Rows r
cross join @Cols c
where Row % Col=0
) p
pivot
(
count(Row) for Col in ([1],[2],[3],[4],[5],[6],[7],[8],[9])
) AS pvt
) as x
Did you find something incorrect/wrong with this solution? Take a few seconds to Report It.
Did you understand how this solution work? If you find it difficult to understand, you can Request an Explanation or you can Write an explanation to help others better understand this solution.